(2x+3)(3x+1)=6x^2+11x+3

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Solution for (2x+3)(3x+1)=6x^2+11x+3 equation: 



(2x+3)(3x+1)=6x^2+11x+3

We move all terms to the left:

(2x+3)(3x+1)-(6x^2+11x+3)=0

We get rid of parentheses

-6x^2+(2x+3)(3x+1)-11x-3=0

We multiply parentheses ..

-6x^2+(+6x^2+2x+9x+3)-11x-3=0

We get rid of parentheses

-6x^2+6x^2+2x+9x-11x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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